Input : [[0, 2], [1, 4], [2, 6]]
Description : I need to print two lists with greater value by comparing the element in the 2nd place.
Expected Output: [[1, 4], [2, 6]]
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Did it help @Santhosh ? remember to upvote/accept if so. See [What should I do when someone answers my question?](https://stackoverflow.com/help/someone-answers) – yatu Mar 04 '19 at 11:15
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Use duplicate to sort - slice as many as you want (2) from sorted result. – Patrick Artner Mar 04 '19 at 13:59
1 Answers
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You can use sorted and specify in the key argument that you want to sort each sublist by the second element using operator.itemgetter. Then slice the returned list to select the two last sublists:
l = [[0, 2], [1, 4], [2, 6]]
from operator import itemgetter
sorted(l, key=itemgetter(1))[-2:]
Output
[[1, 4], [2, 6]]
yatu
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What is it that you'd like some explanation on @Navi ? They functionality of `key`? What itemgetter does? – yatu Mar 04 '19 at 11:14
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1itemgetter is a simple way to fetch an item from its operand, a list in this case. Try doing for example `itemgetter(1)([1,2,3,4])`. This will return the second items in the list. Hope this helps... for more details read [this](https://docs.python.org/2/library/operator.html) – yatu Mar 04 '19 at 11:52
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And check the docs, you can also specify `reverse` asan argument for sorted – yatu Mar 05 '19 at 09:40