How can I compile all .cpp files except one using g++?

Question

To compile all C++ files in my source directory I run

g++ -std=c++17 ../src/*.cpp -o ../out/a.out

How can I compile all cpp files in a given directory except for main.cpp?

We could glob into an array (`files=(../src/*.cpp)`) and then [remove an element from a Bash array](/q/16860877) — Toby Speight, Feb 27 '19 at 15:03

score 4 · Accepted Answer · answered Feb 27 '19 at 15:09

4

bash:

shopt -s extglob
g++ -std=c++17 ../src/!(main).cpp -o ../out/a.out

answered Feb 27 '19 at 15:09

glenn jackman

I *knew* there was an `extglob` solution! Just couldn't quite remember the syntax. Thanks! – Toby Speight Feb 27 '19 at 15:11
What exactly does `shopt -s extglob` do? – K. Claesson Feb 27 '19 at 15:12
1

It enables the *extended patterns* that extend plain glob wildcards into something closer to regular expressions. Read that section of the manual that I linked for you. – glenn jackman Feb 27 '19 at 15:14

score 1 · Answer 2 · answered Feb 27 '19 at 14:53

1

for f in $(find /path/to/files -name "*.cpp" ! -name "main.cpp")
do
  g++ -std=c++17 path/to/files/"$f" -o /path/to/out/....
done

answered Feb 27 '19 at 14:53

nullPointer

Toby Speight · Answer 3 · 2019-02-27T15:10:31.610

1

We can filter the glob into a Bash array:

unset files
for i in ../src/*.cpp
do test "$i" = '../src/main.cpp' || files+=("$i")
done

g++ -std=c++17 "${files[@]}" -o ../out/a.out

mapfile -d $'\0' -t files < <(printf '%s\0' ../src/*.cpp | grep -zv '/main\.cpp$')
g++ -std=c++17 "${files[@]}" -o ../out/a.out

edited Feb 27 '19 at 15:10

answered Feb 27 '19 at 15:01

Toby Speight

That’s more characters than a cmake or make file which would – trojanfoe Feb 27 '19 at 15:14

3 Answers3