Problems creating an if block

Question

The code that I'm using

    if ($_REQUEST('addOrEdit') == 'add') {
      $stmt2 = $pdo->prepare("insert into ITEM (tracker, date, significance, obsolete, description,data, programs, topics, lastModifiedBy) values (?,?,?,?,?,?,?,?,?");

//      $stmt2->execute(array($tracker,$_REQUEST['date'],$_REQUEST['significance],$_REQUEST['obsolete'],$_REQUEST['description'], null, $_REQUEST[program],$_REQUEST[topic],null);

    }

If I comment out the if line and the closing parenthesis, it works (on AWS LAMP instance). But otherwise this is breaking my page, and when I try to load it, I see nothing but a blank page.

Elsewhere on my page I am echoing out the $_REQUEST['addOrEdit'] and it shows add

The problem appears to be with my if usage(?) What am I doing wrong?

Possible duplicate of https://stackoverflow.com/questions/1475297/phps-white-screen-of-death — 04FS, Feb 22 '19 at 11:37
@04FS Thank you for this link. I'm hopeful that this is going to speed up my development greatly! — ControlAltDel, Feb 22 '19 at 14:53

score 2 · Accepted Answer · answered Feb 22 '19 at 11:35

2

You wrote braces to fetch request parameters in if statement. Replace Braces to square brackets.

if ($_REQUEST['addOrEdit'] == 'add') {

answered Feb 22 '19 at 11:35

Rahul

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score 0 · Answer 2 · answered Feb 22 '19 at 11:41

Besides the syntax error (which may be a typo as your question contains the correct syntax later on), as Rahul has pointed out, you could be more defensive and check the key exists within the array.

if (array_key_exists('addOrEdit', $_REQUEST) && $_REQUEST['addOrEdit'] === 'add') {

score 0 · Answer 3 · answered Feb 22 '19 at 11:42

0

$_REQUEST is a global variable of type array.Its not a function. You can access the variable using [] not this (). so try this

if($_REQUEST['addOrEdit'] == 'add'){ your code }

answered Feb 22 '19 at 11:42

devil

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Problems creating an if block

3 Answers3