How to show numerical date in mm/dd/yy format

Question

Right now i am the month, day, and year of a user seperated in three db fields titled month, day, year.

When i display it i am doing:

$month = $row['month'];
$day = $row['day'];
$year = $row['year'];

then to echo it:

$month/$day/$year

The problem is that the PHP is doing mathematics here and dividing the numbers... What can i do to not make that happen and let it simply display the dates..

Thanks

After correcting your code to use string concatenation, fix your database to use a single `DATE` field. — Matthew, Mar 28 '11 at 18:57

score 2 · Answer 1 · answered Mar 28 '11 at 18:51

2

echo $month.'/'.$day.'/'.$year;

answered Mar 28 '11 at 18:51

Andrew Jackman

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score 2 · Accepted Answer · answered Mar 28 '11 at 18:52

2

try this out :

echo "{$month}/{$day}/{$year}";

answered Mar 28 '11 at 18:52

Naftali

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score 2 · Answer 3 · answered Mar 28 '11 at 18:54

2

date('m/d/Y',strtotime($month . ' ' . $day . ' ' . $year));

The advantage of this is that you can choose how to format the date independent of how it is stored in your database: http://php.net/manual/en/function.date.php

answered Mar 28 '11 at 18:54

DADU

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score 1 · Answer 4 · edited May 23 '17 at 12:26

1

echo $month . "/" . $day . "/" . $year;

Doing string concatenation.

or

echo "{$month}/{$day}/{$year}";

Doing string interpolation.

See the difference/performance of the two here.

edited May 23 '17 at 12:26

Community

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answered Mar 28 '11 at 18:52

Mike Lewis

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How to show numerical date in mm/dd/yy format

4 Answers4