Hard binding vs call

Asked Feb 06 '19 at 20:26

Active Feb 06 '19 at 20:26

Viewed 43 times

In my example, do bind and call achieve the same thing, it's just that bind creates a new function?

function hardBinding(a,b){
    this.a = a;
    this.b = b;
    console.log(this);
}

hardBinding = hardBinding.bind(this,a,b);
hardBinding();

function sameAs(){
    hardBinding.call(this,a,b);
}

sameAs();

asked Feb 06 '19 at 20:26

paddyfields

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They are the same, except for the fact that `this` inside sameAs is already not the same as `this` outside it (unless you're not in strict mode and the `this` outside is different too). – Paul Feb 06 '19 at 20:29
They would be completely identical if you used `.bind(x,a,b)` and `.call(x,a,b)`. – Paul Feb 06 '19 at 20:30
https://stackoverflow.com/a/15455043/2813224 – zer00ne Feb 06 '19 at 20:31
1

@zer00ne - thank you. – paddyfields Feb 06 '19 at 20:32
`.call(this,a,b)` is same as `.bind(this,a,b)()` and `.bind(this,a)(b)` and `.bind(this)(a,b)` – Slai Feb 06 '19 at 20:34

Hard binding vs call

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