What does [^)] do in this regex / *\([^)]*\) */g

Question

I am able to achieve the same functionality using the regex / *\(\w+\) */g but i wanted to know what does [^)] do in the following regex expression

let str = "Hello, this is Mike (example)";
str.replace(/ *\([^)]*\) */g, "");

Answer 1

In [] ( character class ) ^ means negation.

so this means [^)]+ Match anything except )

let str = "Hello, this is Mike (example)";
  
let op = str.replace(/ *\([^)]*\) */g, "");

console.log(op)

For more info you can read here Character class and negation