Read Shell Script option separated by space

Question

I have this shell script:

for i in "$@"
do
case $i in
    -l=*|--ddloc=*)
    DDLOC="${i#*=}"
    shift # past argument=value
    ;;
    *)
          # unknown option
    ;;
esac
done

Its working fine as -x=y but i want to be like -x y. What changes will be required here?

Hava a look at `getopt` or builtin `getopts`. – oliv Jan 25 '19 at 13:22 — oliv, Jan 25 '19 at 13:22

jhnc · Accepted Answer · 2019-01-27T17:06:58.573

1

for i in "$@"
do
case $i in
    -l=*|--ddloc=*)
    DDLOC="${i#*=}"
    shift # past argument=value
    ;;
    -l|--ddloc)
    shift # past argument
    DDLOC="$1"
    shift # past value
    ;;
    *)
          # unknown option
    ;;
esac
done

edited Jan 27 '19 at 17:06

answered Jan 27 '19 at 16:57

jhnc

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I think this is a syntax error, you miss `;;` before `*)`, right? – KamilCuk Jan 27 '19 at 17:02
@KamilCuk sorry, yes. Thanks. – jhnc Jan 27 '19 at 17:08

Read Shell Script option separated by space

1 Answers1