I want to calculate a^b%m where a,b and m are very large number like 2^256 or 2^512 bit. As far I know some method called bigmod or powmod which calculate a^b%m in O(log m) time complexity but as the number is huge we need to implement it using BigIntegers. Which is slower than normal arithmetic operation. So for this job I have implemented my own Biginteger library and implemented a O(log m) algorithm to calculate a^b%m. But it is using minimum 7-8 seconds to execute where python pow(a,b,m) function is working in less than 1 second. So I want to know the details about the algorithm which is used to implement pow(a,b,m).
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President James K. Polk
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Tanmoy Datta
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1BigIntegers are not a thing in Python. Regular integers will do just fine. What is your question? – roganjosh Dec 23 '18 at 00:17
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4All of CPython is available of github for you to view – roganjosh Dec 23 '18 at 00:18
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See: https://stackoverflow.com/questions/5246856/how-did-python-implement-the-built-in-function-pow – robert Dec 23 '18 at 00:25