236

According to the docs:

componentDidUpdate() is invoked immediately after updating occurs. This method is not called for the initial render.

We can use the new useEffect() hook to simulate componentDidUpdate(), but it seems like useEffect() is being ran after every render, even the first time. How do I get it to not run on initial render?

As you can see in the example below, componentDidUpdateFunction is printed during the initial render but componentDidUpdateClass was not printed during the initial render.

function ComponentDidUpdateFunction() {
  const [count, setCount] = React.useState(0);
  React.useEffect(() => {
    console.log("componentDidUpdateFunction");
  });

  return (
    <div>
      <p>componentDidUpdateFunction: {count} times</p>
      <button
        onClick={() => {
          setCount(count + 1);
        }}
      >
        Click Me
      </button>
    </div>
  );
}

class ComponentDidUpdateClass extends React.Component {
  constructor(props) {
    super(props);
    this.state = {
      count: 0,
    };
  }

  componentDidUpdate() {
    console.log("componentDidUpdateClass");
  }

  render() {
    return (
      <div>
        <p>componentDidUpdateClass: {this.state.count} times</p>
        <button
          onClick={() => {
            this.setState({ count: this.state.count + 1 });
          }}
        >
          Click Me
        </button>
      </div>
    );
  }
}

ReactDOM.render(
  <div>
    <ComponentDidUpdateFunction />
    <ComponentDidUpdateClass />
  </div>,
  document.querySelector("#app")
);
<script src="https://unpkg.com/react@16.7.0-alpha.0/umd/react.development.js"></script>
<script src="https://unpkg.com/react-dom@16.7.0-alpha.0/umd/react-dom.development.js"></script>

<div id="app"></div>
Yangshun Tay
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    may I ask what is the use case when it makes sense to do something based on number of renders and not an explicit state variable like `count`? – Aprillion Nov 15 '18 at 15:20
  • @Aprillion, in my case change the content of an H2 that has a text that need to change after the list of item, is empty and was even different at beginning. The same list is also empty at beginning before data fetch from API so with normal conditional rendering based on array length the inititial value is overrrided – Carmine Tambascia Nov 05 '21 at 14:32

13 Answers13

226

We can use the useRef hook to store any mutable value we like, so we could use that to keep track of if it's the first time the useEffect function is being run.

If we want the effect to run in the same phase that componentDidUpdate does, we can use useLayoutEffect instead.

Example

const { useState, useRef, useLayoutEffect } = React;

function ComponentDidUpdateFunction() {
  const [count, setCount] = useState(0);

  const firstUpdate = useRef(true);
  useLayoutEffect(() => {
    if (firstUpdate.current) {
      firstUpdate.current = false;
      return;
    }

    console.log("componentDidUpdateFunction");
  });

  return (
    <div>
      <p>componentDidUpdateFunction: {count} times</p>
      <button
        onClick={() => {
          setCount(count + 1);
        }}
      >
        Click Me
      </button>
    </div>
  );
}

ReactDOM.render(
  <ComponentDidUpdateFunction />,
  document.getElementById("app")
);
<script src="https://unpkg.com/react@16.7.0-alpha.0/umd/react.development.js"></script>
<script src="https://unpkg.com/react-dom@16.7.0-alpha.0/umd/react-dom.development.js"></script>

<div id="app"></div>
Tholle
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    I tried to replace `useRef` with `useState`, but using the setter triggered a re-render, which is not happening when assigning to `firstUpdate.current` so I guess this is the only nice way :) – Aprillion Nov 15 '18 at 15:16
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    Could someone explain why use layout effect if we're not mutating or measuring the DOM? – ZenVentzi Mar 06 '19 at 12:45
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    @ZenVentzi It's not necessary in this example, but the question was how to mimic `componentDidUpdate` with hooks, so that's why I used it. – Tholle Mar 06 '19 at 12:52
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    I created a custom hook [here](https://stackoverflow.com/a/53254028/1541563) based on this answer. Thanks for the implementation! – Patrick Roberts Nov 05 '19 at 20:09
132

You can turn it into custom hooks, like so:

import React, { useEffect, useRef } from 'react';

const useDidMountEffect = (func, deps) => {
    const didMount = useRef(false);

    useEffect(() => {
        if (didMount.current) func();
        else didMount.current = true;
    }, deps);
}

export default useDidMountEffect;

Usage example:

import React, { useState, useEffect } from 'react';

import useDidMountEffect from '../path/to/useDidMountEffect';

const MyComponent = (props) => {    
    const [state, setState] = useState({
        key: false
    });    

    useEffect(() => {
        // you know what is this, don't you?
    }, []);

    useDidMountEffect(() => {
        // react please run me if 'key' changes, but not on initial render
    }, [state.key]);    

    return (
        <div>
             ...
        </div>
    );
}
// ...
Mehdi Dehghani
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    This approach throws warnings saying that dependency list is not an array literal. – theprogrammer Oct 26 '19 at 05:57
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    I use this hook in my projects and I didn't see any warning, could you provide more info? – Mehdi Dehghani May 04 '20 at 15:50
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    @vsync You're thinking about a different case where you want to run an effect once on initial render and never again – Programming Guy May 21 '20 at 03:13
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    @vsync In the notes section of https://reactjs.org/docs/hooks-effect.html#tip-optimizing-performance-by-skipping-effects it specifically says "If you want to run an effect and clean it up only once (on mount and unmount), you can pass an empty array ([]) as a second argument." This matches observed behaviour for me. – Programming Guy May 22 '20 at 09:58
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    I also receive the warnings for dependency list is not an array literal and missing dependency: 'func'. The linter rule noted for both is react-hooks/exhaustive-deps – plong0 Feb 23 '21 at 21:36
  • @plong0 Okay, I tested the mentioned code (in my answer) and I didn't get any warning, I think it is related to react version that you using or your dependency (`state.key` in my answer), so I need more info in order to give you better answer. – Mehdi Dehghani Feb 24 '21 at 05:22
  • No need to import `React` in your hook file – gogaz Jun 03 '21 at 10:33
  • he forgot do add: `[]` around deps... should be something like `[deps]`... but it doesnt work for me – Carlos Eduardo Olivera Filho Sep 07 '21 at 21:59
  • @CarlosEduardoOliveraFilho I didn't forgot, it is not the case. when you using this hook you should pass the dependencies as array, just like `useEffect` itself. write your code using `useEffect`, if everything works then simple change the `useEffect` to `useDidMountEffect` and you are good to go. – Mehdi Dehghani Sep 08 '21 at 03:22
  • @Mehdi oh, okay, youre right, im sorry, deps received as a parameter to your custom hook is already an array thats why u dont need the [ ]. Thanks! – Carlos Eduardo Olivera Filho Sep 09 '21 at 07:35
  • There is absolutely no reason for the empty `useEffect()` to be there – fullStackChris Jan 08 '22 at 15:16
  • You just need `return func()` to send the return value to `useEffect`, in case it's a destructor (ie, cleanup function). – skot May 18 '22 at 17:50
56

I made a simple useFirstRender hook to handle cases like focussing a form input:

import { useRef, useEffect } from 'react';

export function useFirstRender() {
  const firstRender = useRef(true);

  useEffect(() => {
    firstRender.current = false;
  }, []);

  return firstRender.current;
}

It starts out as true, then switches to false in the useEffect, which only runs once, and never again.

In your component, use it:

const firstRender = useFirstRender();
const phoneNumberRef = useRef(null);

useEffect(() => {
  if (firstRender || errors.phoneNumber) {
    phoneNumberRef.current.focus();
  }
}, [firstRender, errors.phoneNumber]);

For your case, you would just use if (!firstRender) { ....

Marius Marais
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  • If you add the `firstRender` to the array of dependencies in the useEffect, this will run twice (the first time, and when firstRender is set to false) when mounting. I removed it from the dependencies in my code and it worked. – Rafael Duarte Apr 13 '22 at 10:54
9

Same approach as Tholle's answer, but using useState instead of useRef.

const [skipCount, setSkipCount] = useState(true);

...

useEffect(() => {
    if (skipCount) setSkipCount(false);
    if (!skipCount) runYourFunction();
}, [dependencies])

EDIT

While this also works, it involves updating state which will cause your component to re-render. If all your component's useEffect calls (and also all of its children's) have a dependency array, this doesn't matter. But keep in mind that any useEffect without a dependency array (useEffect(() => {...}) will be run again.

Using and updating useRef will not cause any re-renders.

Luigi
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8

@ravi, yours doesn't call the passed-in unmount function. Here's a version that's a little more complete:

/**
 * Identical to React.useEffect, except that it never runs on mount. This is
 * the equivalent of the componentDidUpdate lifecycle function.
 *
 * @param {function:function} effect - A useEffect effect.
 * @param {array} [dependencies] - useEffect dependency list.
 */
export const useEffectExceptOnMount = (effect, dependencies) => {
  const mounted = React.useRef(false);
  React.useEffect(() => {
    if (mounted.current) {
      const unmount = effect();
      return () => unmount && unmount();
    } else {
      mounted.current = true;
    }
  }, dependencies);

  // Reset on unmount for the next mount.
  React.useEffect(() => {
    return () => mounted.current = false;
  }, []);
};
Whatabrain
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  • Hello @Whatabrain, how to use this custom hook on passing non-depdendency list? Not an empty which would be the same as componentDidmount but something like `useEffect(() => {...});` – Kev D. Aug 04 '20 at 02:20
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    @KevDing Should be as simple as omitting the `dependencies` parameter when you call it. – Whatabrain Aug 05 '20 at 15:27
  • You can lose the second `useEffect`. It's not doing anything. That ref you're resetting is going straight in the garbage. If there's a "next mount" it will happen to a different instance of the hook with a `mounted` ref all its own, initialized to false. – skot May 16 '22 at 02:38
  • And ```const unmount = effect(); return () => unmount && unmount();``` can be simplified to ```return effect()``` – skot May 16 '22 at 02:42
  • @skot I wrote the second effect for completeness, but in the next version of React, multiple mounts and unmounts will be possible, making it more necessary. Good catch on the unmount simplification. You're right! – Whatabrain May 17 '22 at 15:28
2

This is the best implementation I've created so far using typescript. Basically, the idea is the same, using the Ref but I'm also considering the callback returned by useEffect to perform cleanup on component unmount.

import {
  useRef,
  EffectCallback,
  DependencyList,
  useEffect
} from 'react';

/**
 * @param effect 
 * @param dependencies
 *  
 */
export default function useNoInitialEffect(
  effect: EffectCallback,
  dependencies?: DependencyList
) {
  //Preserving the true by default as initial render cycle
  const initialRender = useRef(true);

  useEffect(() => {
    let effectReturns: void | (() => void) = () => {};

    // Updating the ref to false on the first render, causing
    // subsequent render to execute the effect
    if (initialRender.current) {
      initialRender.current = false;
    } else {
      effectReturns = effect();
    }

    // Preserving and allowing the Destructor returned by the effect
    // to execute on component unmount and perform cleanup if
    // required.
    if (effectReturns && typeof effectReturns === 'function') {
      return effectReturns;
    } 
    return undefined;
  }, dependencies);
}

You can simply use it, as usual as you use the useEffect hook but this time, it won't run on the initial render. Here is how you can use this hook.

useuseNoInitialEffect(() => {
  // perform something, returning callback is supported
}, [a, b]);

If you use ESLint and want to use the react-hooks/exhaustive-deps rule for this custom hook:

{
  "rules": {
    // ...
    "react-hooks/exhaustive-deps": ["warn", {
      "additionalHooks": "useNoInitialEffect"
    }]
  }
}
Dominik
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Kiran Maniya
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1

@MehdiDehghani, your solution work perfectly fine, one addition you have to do is on unmount, reset the didMount.current value to false. When to try to use this custom hook somewhere else, you don't get cache value.

import React, { useEffect, useRef } from 'react';

const useDidMountEffect = (func, deps) => {
    const didMount = useRef(false);

    useEffect(() => {
        let unmount;
        if (didMount.current) unmount = func();
        else didMount.current = true;

        return () => {
            didMount.current = false;
            unmount && unmount();
        }
    }, deps);
}

export default useDidMountEffect;
Whatabrain
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ravi
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    I'm not sure this is necessary, since if the component does end up unmounting, because if it does remount, didMount will already be re-initialized to `false`. – Cameron Yick Apr 29 '20 at 14:37
  • @CameronYick it's necessary because when using Fast Refresh the cleanup function will run, but the ref value won't get cleared. This results in glitches while developing - but in production it would be fine. – andreialecu Apr 13 '21 at 07:49
  • I think this is going to set `didMount.current` to false every time the deps change, and thus never fire the effect! Am I wrong? That `didMount` reset, if we want it at all, would need to live in a separate `useEffect` whose deps are `[]` – skot May 16 '22 at 01:01
  • Yeah, what I'm seeing when I use this code is the effect never fires at all. – skot May 16 '22 at 01:09
1

a simple way is to create a let, out of your component and set in to true.

then say if its true set it to false then return (stop) the useEffect function

like that:


    import { useEffect} from 'react';
    //your let must be out of component to avoid re-evaluation 
    
    let isFirst = true
    
    function App() {
      useEffect(() => {
          if(isFirst){
            isFirst = false
            return
          }
    
        //your code that don't want to execute at first time
      },[])
      return (
        <div>
            <p>its simple huh...</p>
        </div>
      );
    }

its Similar to @Carmine Tambasciabs solution but without using state :) ‍‍‍‍‍‍ ‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

scripty dude
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0

Simplified implementation

import { useRef, useEffect } from 'react';

function MyComp(props) {

  const firstRender = useRef(true);

  useEffect(() => {
    if (firstRender.current) {
      firstRender.current = false;
    } else {
      myProp = 'some val';
    };

  }, [props.myProp])


  return (
    <div>
      ...
    </div>
  )

}
shahul01
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0

Keep it simple:

function useEffectAfterFirstRender(effect, deps) {
  const isFirstRender = useRef(true);

  useEffect(() => {
    if (isFirstRender.current) isFirstRender.current = false;
    else return effect();
  }, deps);
}

Other solutions here reduce to this if you remove unnecessary complications:

  • We need to pass the return value of effect(), because it might be a destructor, but we don't need to do any conditional logic to determine if it is or isn't. Just pass it on, whatever it is, and let useEffect figure it out.
  • There's no point in resetting isFirstRender to true on unmount, because 1) the condition hasn't become true, and 2) on unmount, that ref is going in the incinerator. It doesn't get reused on the "next mount." There is no next mount. Unmount is death.

Here it is as a complete typescript module:

import { useEffect, useRef, EffectCallback, DependencyList } from 'react';

function useEffectAfterFirstRender(effect: EffectCallback, deps: DependencyList): void {
  const isFirstRender = useRef(true);

  useEffect(() => {
    if (isFirstRender.current) isFirstRender.current = false;
    else return effect();
    // eslint-disable-next-line react-hooks/exhaustive-deps
  }, deps);
}

export default useEffectAfterFirstRender;

And I upvote Kiran Maniya's suggestion to give it an exhaustive-deps eslint rule:

{
  "rules": {
    "react-hooks/exhaustive-deps": ["warn", {
      "additionalHooks": "useEffectAfterFirstRender"
    }]
  }
}
skot
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0

I thought creating a custom hook would be overkill and I didn't want to muddle my component's readability by using the useLayoutEffect hook for something unrelated to layouts, so, in my case, I simply checked to see if the value of my stateful variable selectedItem that triggers the useEffect callback is its original value in order to determine if it's the initial render:

export default function MyComponent(props) {
    const [selectedItem, setSelectedItem] = useState(null);

    useEffect(() => {
        if(!selectedItem) return; // If selected item is its initial value (null), don't continue
        
        //... This will not happen on initial render

    }, [selectedItem]);

    // ...

}
A__
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-1

If you want to skip the first render, you can create a state "firstRenderDone" and set it to true in the useEffect with empty dependecy list (that works like a didMount). Then, in your other useEffect, you can check if the first render was already done before doing something.

const [firstRenderDone, setFirstRenderDone] = useState(false);

//useEffect with empty dependecy list (that works like a componentDidMount)
useEffect(() => {
  setFirstRenderDone(true);
}, []);

// your other useEffect (that works as componetDidUpdate)
useEffect(() => {
  if(firstRenderDone){
    console.log("componentDidUpdateFunction");
  }
}, [firstRenderDone]);
  • I used this, I don't see what's wrong with this, if someone could explain why negative points? – Gishas Apr 04 '22 at 09:43
  • This outputs "componentDidUpdateFunction" on the second render only, not on any subsequent ones. If you take `firstRenderDone` out of the deps arrray, this will work. – skot May 18 '22 at 18:05
  • But it's not as tidy as the `useRef`-based solutions because your first render immediately triggers the second one. So you get a `componentDidUpdate` event right away, but all that's actually updating is the variable you're using to avoid triggering an update right away. – skot May 18 '22 at 18:14
-1

All previous are good, but this can be achieved in a simplier way considering that the action in useEffect can be "skipped" placing an if condition(or any other ) that is basically not run first time, and still with the dependency.

For example I had the case of :

  1. Load data from an API but my title has to be "Loading" till the date were not there, so I have an array, tours that is empty at beginning and show the text "Showing"
  2. Have a component rendered with different information from those API.
  3. The user can delete one by one those info, even all making the tour array empty again as the beginning but this time the API fetch is been already done
  4. Once the tour list is empty by deleting then show another title.

so my "solution" was to create another useState to create a boolean value that change only after the data fetch making another condition in useEffect true in order to run another function that also depend on the tour length.

useEffect(() => {
  if (isTitle) {
    changeTitle(newTitle)
  }else{
    isSetTitle(true)
  }
}, [tours])

here my App.js

import React, { useState, useEffect } from 'react'
import Loading from './Loading'
import Tours from './Tours'

const url = 'API url'

let newTours

function App() {
  const [loading, setLoading ] = useState(true)
  const [tours, setTours] = useState([])
  const [isTitle, isSetTitle] = useState(false)
  const [title, setTitle] = useState("Our Tours")

  const newTitle = "Tours are empty"

  const removeTours = (id) => {
    newTours = tours.filter(tour => ( tour.id !== id))

    return setTours(newTours)
  }

  const changeTitle = (title) =>{
    if(tours.length === 0 && loading === false){
      setTitle(title)
    }
  }

const fetchTours = async () => {
  setLoading(true)

  try {
    const response = await fetch(url)
    const tours = await response.json()
    setLoading(false)
    setTours(tours)
  }catch(error) {
    setLoading(false)
    console.log(error)
  }  
}


useEffect(()=>{
  fetchTours()
},[])

useEffect(() => {
  if (isTitle) {
    changeTitle(newTitle)
  }else{
    isSetTitle(true)
  }
}, [tours])


if(loading){
  return (
    <main>
      <Loading />
    </main>
  )  
}else{
  return ( 

    <main>
      <Tours tours={tours} title={title} changeTitle={changeTitle}           
removeTours={removeTours} />
    </main>
  )  
 }
}



export default App
Carmine Tambascia
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  • I see no difference in this approach, except for the order of the conditions on the if statement. – Luigi Nov 06 '21 at 16:17
  • @Luigi is not really the same as your if check the same variable, so either one or the other is run, In my use case first if change the title variable the second set back the state variable to true – Carmine Tambascia Dec 10 '21 at 22:03
  • that's what I mean with the order changed. you check if you've set it before, and if you have, you run your function. mine first checks if i've haven't set it yet, and then sets it. otherwise, it runs my function (in your case, changeTitle). – Luigi Dec 12 '21 at 01:18
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    @Luigi I have tried your approach once I had this use case and wasn't working, then I came up with what I wrote above and again I check 2 different variable. At the moment I am over other thins, but I will explain it better why I had to check 2 different variable not the same one. Also there isn't need to downgrade others people answer if they aren't clear. I provided an almost full example, so eventually could be an enhancement of yours, but is more and edge case, otherwise I could have simply have used others answers, included yours. – Carmine Tambascia Feb 03 '22 at 06:38
  • I didn't downvote it. Your answer works. – Luigi Feb 10 '22 at 14:05