extracting string within python list

Question

How do I split this:

str = "['A20150710', 1.0]" to get 'A20150710'?

I tried the below line but not sure how to proceed from there:

str.split(',')

Let's take a step back, how did you get this: `str = "['A20150710', 1.0]"`? That looks like a string representation of a list. Indeed, your title implies that, but note, **there are no lists here** — juanpa.arrivillaga, Oct 25 '18 at 16:57

Austin · Answer 1 · 2018-10-25T16:58:46.443

3

Use ast.literal_eval to convert string representation to a list and get the first item:

import ast

str = "['A20150710', 1.0]"

print(ast.literal_eval(str)[0])
# A20150710

edited Oct 25 '18 at 16:58

answered Oct 25 '18 at 16:57

Austin

1

this is almost certainly a duplicate if this is the case. – juanpa.arrivillaga Oct 25 '18 at 16:58

score 1 · Answer 2 · answered Oct 25 '18 at 16:58

1

Split on , and remove punctuations

import string
str1 = "['A20150710', 1.0]"
str1=str1.split(',')[0]
str1.translate(None,string.punctuation) #'A20150710'

answered Oct 25 '18 at 16:58

mad_

score 1 · Answer 3 · answered Oct 25 '18 at 17:00

1

Use eval to parse the string, then fetch the information you want

str = "['A20150710', 1.0]"
eval(str)[0] # A20150710

!!!Be careful!!! Using eval is a security risk, as it executes arbitrary Python expressions

answered Oct 25 '18 at 17:00

Andrei Cioara

3 Answers3