Javascript get two smallest numbers from array

Question

I want to get two smallest numbers from array with three numbers

I can only get one smallest number from array. I can't get two numbers. Can anyone help me?

var array = [2, 3, 5];

var min = Math.min(array[0], array[1], array[2]);
console.log(min)

You could sort the array ascending and then just .pop() the last number off of the array? — Jack hardcastle, Oct 23 '18 at 12:38
sort, then slice the sorted array ... ascending order ... `array.slice().sort((a, b) => a - b).slice(0, 2)` ... descending order `array.slice().sort((a, b) => b - a).slice(-2)` — Jaromanda X, Oct 23 '18 at 12:40
in the duplicate, the answer fails to mention the original array is mutated — Jaromanda X, Oct 23 '18 at 12:45

Rafael Herscovici · Answer 1 · 2018-10-23T12:48:55.070

0

Sort your array by value and grab the two first results:

var arr = [5,3,10,4,9,1];
arr.sort((a, b) => a - b);
console.log(arr[0], arr[1]);

edited Oct 23 '18 at 12:48

answered Oct 23 '18 at 12:40

Rafael Herscovici

1

sort sorts in place, so no need to add arr=arr.sort ... just arr.sort ... of course, one may not want the original array mutated – Jaromanda X Oct 23 '18 at 12:46

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