Regex to get text after a specific word?

Question

How to get text inside quote("asd") after value -> "name": like:

"name":"John","name":"1-John", "name":"123", "name":"123","name":"A0-0s".

I need to get all inside quote(""):

John
1-John
123
A0-0s

Look at the javadoc of [`Pattern`](https://docs.oracle.com/javase/10/docs/api/java/util/regex/Pattern.html) and play around with [Regex101.com](https://regex101.com/). — Joop Eggen, Oct 10 '18 at 11:26

score 2 · Accepted Answer · answered Oct 10 '18 at 11:28

2

You can use the following regex with lookbehind:

(?<="name":")[^"]+

Demo: https://regex101.com/r/TfkNXE/1

answered Oct 10 '18 at 11:28

blhsing

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The Scientific Method · Answer 2 · 2018-10-10T11:39:52.430

0

You can use the following regex

[\w-]+(?=")

Demo at regex 101

edited Oct 10 '18 at 11:39

answered Oct 10 '18 at 11:30

The Scientific Method

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score 0 · Answer 3 · answered Oct 10 '18 at 11:32

The regular expression you can use is: \"name\":\"([a-zA-Z0-9--])+\". Due to the brackets '()' the required result will be present in the first group of the regex match.

However in case you have multiple combinations in a single string like the one you had in the example, remember to use find() or search() method and read more about search and match methods.

Regex to get text after a specific word?

3 Answers3