python built-in function for float to int in specific case

Asked Sep 25 '18 at 11:10

Active Sep 25 '18 at 11:15

Viewed 63 times

I have a function which return float value for example 4.0 or 4.8

I want if the function returns 4.0 then it should print 4 only but if it return any other value example- 4.1, 4.3, 4.8 then it should print as it is.

I know this can be done through conditions or by making custom functions but i wanted to know is there any builtin function in python by which i can do this.

asked Sep 25 '18 at 11:10

Chandella07

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Are you asking if there's a function to check for fractional part in a float? – Mad Physicist Sep 25 '18 at 11:13
yes something on fractional part if it is 4.0 then print 4 only if 4.8 then 4.8 only. – Chandella07 Sep 25 '18 at 11:14
@Aran-Fey. Another approach: https://stackoverflow.com/q/21583758/2988730 – Mad Physicist Sep 25 '18 at 11:14
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As far as I know there is no builtin function for printing like this, however there is a builtin function to check whether a number is an integer, namely `float.is_integer()`, e.g. `(4.8).is_integer()` yields `False` and `(4.0).is_integer()` yields `True` – Thijs van Ede Sep 25 '18 at 11:15
@ThijsvanEde yup https://stackoverflow.com/a/16577771/6451573 – Jean-François Fabre Sep 25 '18 at 11:16
Neat. I didn't know you could edit the list of duplicates once the question is hammered. – Mad Physicist Sep 25 '18 at 11:17
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You can try: `print(str(x).rstrip('.0')` – John Go-Soco Sep 25 '18 at 11:20

python built-in function for float to int in specific case

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