How to split a string in python with a remainder?

Question

In python3 I have e.g. the following string

 433 65040    9322 /opt/conda/envs/python2/bin/python -m ipykernel_launcher

which I want to split in four parts: the first three elements (the numbers) and the remainder as one string. Of course its possible to do it the following way:

text = " 433 65040    9322 /opt/conda/envs/python2/bin/python -m ipykernel_launcher"
pid,rss,etime,*remainder = text.split()
cmd = ' '.join(remainder)

but maybe there is a more pythonic way to do that?

you could consider using https://psutil.readthedocs.io/ . that does not help with string splitting but with process info in python... — hiro protagonist, Sep 20 '18 at 11:53
I don't think that is a good duplicate for this question, that is not what the OP is asking — Cory Kramer, Sep 20 '18 at 11:53
@CoryKramer Isn't it? As I see it, it's exactly the same question with `maxsplit=1`. — Aran-Fey, Sep 20 '18 at 11:55
Now that I think about it yeah you're right that's a good solution, but with `maxsplit=3`, then that would do the trick — Cory Kramer, Sep 20 '18 at 11:56

score 2 · Answer 1 · answered Sep 20 '18 at 11:54

2

You can use split with the maxsplit parameter:

text = " 433 65040    9322 /opt/conda/envs/python2/bin/python -m ipykernel_launcher"
text.strip().split(maxsplit=3)  # max 3 splits
# ['433', '65040', '9322', '/opt/conda/envs/python2/bin/python -m ipykernel_launcher']

answered Sep 20 '18 at 11:54

user2390182

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note to future self: 3 splits gives 4 outputs – craq Sep 09 '21 at 03:27

How to split a string in python with a remainder?

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