Trying to sort object keys based on child property

Question

I have this object:

var myObject = {
    cat: {
        order: 1
    },

    mouse: {
        order: 4
    },

    dog: {
        order: 2
    },   

    shark: {
        order: 3
    }
}

I'm trying to get back: ["cat", "dog", "shark", "mouse"]

I tried:

_.sortBy(x, function(e) { return e.order} )

Possible duplicate of [Sorting JavaScript Object by property value](https://stackoverflow.com/questions/1069666/sorting-javascript-object-by-property-value) — Dexygen, Sep 12 '18 at 18:53

score 7 · Accepted Answer · answered Sep 12 '18 at 18:50

You can simply use Object.keys() and Array.sort() for it.

get all the keys from the Object using Object.keys().
Simply sort all the keys by passing a custom Comparator to the sort function which compares the order property of the keys in the object.

var myObject = { cat: { order: 1 }, mouse: { order: 4 }, dog: { order: 2 }, shark: { order: 3 } };

let result = Object.keys(myObject).sort((a,b)=> myObject[a].order -  myObject[b].order);

console.log(result);

Thank you, worked well and I like I don't have to map at the end. — Batman, Sep 12 '18 at 19:14

Sphinx · Answer 2 · 2018-09-12T18:55:26.603

use Object.entries first, then sort by the order property of its second element (because Object.entries returns an array of a given object's own enumerable property [key, value] pairs), finally use Array.map to get what you need.

var myObject = {
  cat: {
    order: 1
  },
  mouse: {
    order: 4
  },
  dog: {
    order: 2
  },
  shark: {
    order: 3
  }
}

console.log(
  Object.entries(myObject).sort((a, b) => {
    return a[1].order - b[1].order
  }).map(item => item[0])
)

Steve Bohmbach · Answer 3 · 2018-09-12T19:02:00.163

0

    var myObject = {
    cat: {
        order: 1
    },

    mouse: {
        order: 4
    },

    dog: {
        order: 2
    },   

    shark: {
        order: 3
    }
}     
let oKeys = Object.keys(myObject)

     let tempArray = []

     oKeys.forEach(function(key) {
        tempArray[myObject[key]['order']-1] = key
     })
          
   
     console.log(tempArray)

edited Sep 12 '18 at 19:02

answered Sep 12 '18 at 18:51

Steve Bohmbach

317
1
10

Why use `.map` when you are not using it for mapping functionality? This should be a `.forEach`. Then again, the body of the callback seems to be wrong, too. – VLAZ Sep 12 '18 at 18:54
1

You should consider making a runnable snippet so you can identify the errors it throws. hint: you probably want something more like: `tempArray[myObject[key].order -1] = key` (and forEach as vlaz mentioned) – Mark Sep 12 '18 at 18:54
Thanks for the feedback @MarkMeyer – Steve Bohmbach Sep 12 '18 at 19:03

score 0 · Answer 4 · answered Sep 13 '18 at 05:41

Here is a solution using lodash.

Use _.map and _.sort for it.

First, _.map to array of order and name.
Then, _.sort and _.map name

By using lodash chain, make the code easy to read.

 _(myObject)
   .map((v, k) => ({order: v.order, name: k}))
   .sortBy('order')
   .map('name')
   .value()

Trying to sort object keys based on child property

4 Answers4