Bash: execute files via for-in-loop

Question

for executablefile in ./*.out; do executablefile; done

It should be self-explanatory from the title what I am trying to do in bash. Unfortunately, none of the tutorials online comes close to this. Can you post a working example and explain your changes?

Add a shebang and then paste your script there to get a hint: http://www.shellcheck.net/ — Cyrus, Sep 05 '18 at 06:52
Voted up for shellcheck tool! I also added shellharden analysis tool in a separate answer. — el-teedee, Sep 05 '18 at 08:18

Poshi · Accepted Answer · 2018-09-05T07:03:11.553

0

Have you tried using the proper variable syntax?

for executablefile in ./*.out; do "$executablefile"; done

edited Sep 05 '18 at 07:03

answered Sep 05 '18 at 06:50

Poshi

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Properly speaking you should use double quotes around the variable interpolation, in case the wildcard matches anything which contains shell metacharacters. See also https://stackoverflow.com/questions/10067266/when-to-wrap-quotes-around-a-shell-variable – tripleee Sep 05 '18 at 07:02
Of course not; then I'd have posted a separate answer instead. – tripleee Sep 05 '18 at 07:04

Bash: execute files via for-in-loop

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