Javascript loop use variable from outside loop

Question

I'm trying to do a simple JS loop where I initialize a variable with a value outside the loop, but for some reason its not working.

Basically, I'd like to have total_money equals to 20 in my example, but it keeps returning money

var total = 0;
var money = 20;
var ticker = ['money'];
for (tick in ticker) {
  total_money = ticker[tick];
}

console.log(total_money);

Possible duplicate of [How to find JavaScript variable by its name](https://stackoverflow.com/questions/724857/how-to-find-javascript-variable-by-its-name) — Patrick Roberts, Aug 19 '18 at 21:24

score 0 · Accepted Answer · edited Aug 19 '18 at 21:52

0

Remove the single-quotes '...' from your array called ticker:

var total = 0;
var money = 20;
var ticker = [money]; // <-- Remove the single-quotes
for (tick in ticker) {
  total_money = ticker[tick];
}

console.log(total_money);

edited Aug 19 '18 at 21:52

Dennis Vash

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answered Aug 19 '18 at 21:19

Jed

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score 0 · Answer 2 · answered Aug 19 '18 at 22:07

I know this is a simplified version of the code, but just be aware that you are not adding up total_money but overwriting

So if you have another ticker. For example:

var total = 0;
var money1 = 20;
var money2 = 30;
var ticker = [money1,money2];
for (tick in ticker) {
  total_money = ticker[tick];
}

console.log(total_money);

You will get total_money = 30, not 50.

You can fix this by doing total_money += ticker[tick]

Also note that you are looping through one item.

score 0 · Answer 3 · edited Aug 20 '18 at 03:16

0

The reason is because:

for (tick in ticker) {
  console.log(tick) //tick equal 0
}

edited Aug 20 '18 at 03:16

Grant Miller

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answered Aug 20 '18 at 02:05

Big Yang

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Javascript loop use variable from outside loop

3 Answers3