Python 3 Input(prompt) function

Question

I know this might be a simple question but I can't seem to figure how to put a string after the for loop variable

stud_num = int(input("How many students do you have? "))
test_num = int(input("How many test for your module? "))
score = 0
for i in range(stud_num):
    print("******** Student #", i+1, "********")
    for s in range(test_num):
        print("Test number ", end="")
        score1 = float(input(s+1))
        score += score1

My sample output for asking the question would be

Test number 1 :

but now my current output from

print("Test number ", end="")

score1 = float(input(s+1)) is Test number 1

I can't figure out how to put the ": " into the input because it gives me an error saying that it expects an int but gets a str

@Jean-FrançoisFabre it still doesn't work, it still gives me the same error, expected type int but got str — Kovi, Aug 08 '18 at 08:48
we didn't see `stud_num` and `test_num` but I suppose you forgot to convert to int after input (this isn't a [mcve]) — Jean-François Fabre, Aug 08 '18 at 08:49
then show a [mcve], else it's duplicate of https://stackoverflow.com/questions/20449427/how-can-i-read-inputs-as-integers — Jean-François Fabre, Aug 08 '18 at 08:50

score 1 · Accepted Answer · answered Aug 08 '18 at 08:50

1

Don't split your prompt between a print and the input. Just use a format string in the input prompt:

score1 = float(input("Test number %d: " % (s+1)))

Or using str.format:

score1 = float(input("Test number {}: ".format(s+1)))

answered Aug 08 '18 at 08:50

tobias_k

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@JHBonarius I was trying to but it said I couldn't accept an answer so fast? It's telling me I can accept in 2 mins – Kovi Aug 08 '18 at 08:55
@JHBonarius Haha yea! – Kovi Aug 08 '18 at 08:58

score 0 · Answer 2 · answered Aug 08 '18 at 09:01

0

OR the new f-strings, only allowed after python 3.6:

score1 = float(input(f"Test number {s+1}: "))

answered Aug 08 '18 at 09:01

U12-Forward

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Python 3 Input(prompt) function

2 Answers2