comparing Big Decimal Value

Question

I have a BigDecimal object, which I am checking for its value (greater or smaller than 100).

public static void main(String[] args) {    
    BigDecimal obj = new BigDecimal("100.3");   
    if (obj.intValue() > 100)
    {
        System.out.println("Greater than 100");
    }
    else
    {
        System.out.println("Not greater than 100");
    }   
}

But it's showing:

Not greater than 100

`new BigDecimal("100.3").intValue()` is `100`. And 100 is not greater than 100 — ernest_k, Aug 01 '18 at 07:00

score 1 · Answer 1 · edited Aug 01 '18 at 07:06

The reason your logic fails is that new BigDecimal("100.3").intValue() will (as the method name suggests) give you the value without decimal precision, i.e. 100. And 100 > 100 will be false.

Instead, use compareTo() method of BigDecimal to compare

BigDecimal oneHundred = new BigDecimal("100");
BigDecimal obj = new BigDecimal("100.3");
if (obj.compareTo(oneHundred) > 0) {
    System.out.println("Greader than");
}

comparing Big Decimal Value

1 Answers1