Using remove_reference in function header

Question

Say I have the following:

template <typename... A>
class MyClass
{
public:

    void func(A... args)
    {
        // do stuff
    }
};

What I really want is for func() to take l-value references, so something like this:

template <typename... A>
class MyClass
{
public:

    void func(std::remove_reference<A>::type&... args)
    {
        // do stuff
    }
};

This doesn't compile; is this sort of thing possible? Thanks.

clang error: "error: missing 'typename' prior to dependent type name 'std::remove_reference::type'" — bolov, Jul 31 '18 at 20:11

score 1 · Answer 1 · answered Jul 31 '18 at 20:36

1

The code should read

template <typename... A>
class MyClass
{
public:

    void func(typename std::remove_reference<A>::type&... args)
    {
        // do stuff
    }
};

answered Jul 31 '18 at 20:36

Jason Fernandez

Note that with C++14 you can simply use: `void func(std::remove_reference_t&... args) { ... }` – 0x5453 Jul 31 '18 at 20:39

1 Answers1