Why such script:
x=xxx
y=yyy
printf -v var "%s %s" "$x" "$y"
printf $var
prints only:
xxx
While I expected:
xxx yyy
How to force printf not ignore symbols after blank space?
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Kenenbek Arzymatov
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2`printf "$var"` – Inian Jul 25 '18 at 13:13
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1`printf "$var"` only works if there is no `%s` or similar in the string. Better use `printf "%s\n" "$var"` or plain old simple `echo "$var"`. – Alfe Jul 25 '18 at 13:18
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Or just: `printf '%s' "${x} ${y}"` – Benjamin Barrois Jul 25 '18 at 13:18
1 Answers
0
How about
#!/bin/bash
x=xxx
y=yyy
var=`printf "%s %s" $x $y`
echo $var
?
Jan Myszkier
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