Punctuation special sequence \p fails in regex

Asked Jul 22 '18 at 19:19

Active Jul 22 '18 at 19:19

Viewed 53 times

This thread suggests using \p to match punctuation and the comments suggest it works. But I could not find it in the official documentation and this code fails for me in Python 2.7.10 or Python 3.7.0:

import re

s = """
ABCD?
"""

print("with p: " + str(re.search(r"\n[A-Z \\p]+\n", s)))
print("with ?: " + str(re.search(r"\n[A-Z ?]+\n", s)))

The result is:

with p: None
with ?: <_sre.SRE_Match object at 0x1039afbf8>

Does Python have a special sequence to match punctuation?

asked Jul 22 '18 at 19:19

miguelmorin

4,227
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5

Use PyPi regex module and use `\p{P}` to match punctuation. There is `import regex as re` at the start. – Wiktor Stribiżew Jul 22 '18 at 19:21
1

Note there is an [answer showing how to do that with `re`](https://stackoverflow.com/a/37708340/3832970). – Wiktor Stribiżew Jul 22 '18 at 20:35
Yes indeed, I missed that `regex` was another package. – miguelmorin Jul 23 '18 at 11:53

Punctuation special sequence \p fails in regex

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