Get rows in numpy array where column contains string

Question

I have a numpy array with 4 columns. The first column is text.

I want to retrieve every row in the array where the first column contains a substring.

Example: if the string I'm searching for is "table", find and return all rows in the numpy array whose first column contains "table."

I've tried the following:

rows = nparray[searchString in nparray[:,0]]

but that doesn't seem to work

The array I'm using is literally a pandas dataframe derived from as_matrix(), so it's very much available. What did I miss? — MP12389, Jul 06 '18 at 16:24
This: https://stackoverflow.com/questions/17071871/select-rows-from-a-dataframe-based-on-values-in-a-column-in-pandas#17071908. — Paula Thomas, Jul 06 '18 at 16:27

iacob · Accepted Answer · 2018-07-06T17:45:11.227

1

Given a pandas DataFrame df, this will return all rows where searchString is a substring of the value in the column column:

searchString = "table"

df.loc[df['column'].str.contains(searchString, regex=False)]

edited Jul 06 '18 at 17:45

answered Jul 06 '18 at 17:21

iacob

1

Yep, after Paula Thomas led me down the pandas track, I came across this https://stackoverflow.com/questions/27975069/how-to-filter-rows-containing-a-string-pattern-from-a-pandas-dataframe/27975191, which is the same thing. Thanks! – MP12389 Jul 06 '18 at 17:24
1

Add `regex=False` for a trivial speed-up. – jpp Jul 06 '18 at 17:24

1 Answers1