Multiple bash scripts to execute at a time in a single command

Question

I have three bash scripts which will give output with options.

./script_1 list ./script_2 list ./script_3 list ./script_9 list

and these numbers differs with servers but the first word in every server is "script".

now I want to run all these scripts together with same option 'list'. I need something like ./script_* list ?? or a command with ls or awk or anything else..

Running the process in background is not fulfilling my solution as I appended it into another script.

Why would you think `ls` or `awk` would allow you run your scripts in parallel? — Inian, Jul 06 '18 at 05:41
and why is running in the background not a solution? You can run in the background in a script. — jeremysprofile, Jul 06 '18 at 06:31

score 2 · Accepted Answer · answered Jul 06 '18 at 06:34

2

for i in ./script_*; do
    $i list
done

If this is not the use case you're seeking, you'll have to be more specific in your question.

answered Jul 06 '18 at 06:34

jeremysprofile

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@jeremysprofile : Note that, unless you do a `shopt -s nullglob`, this would produce an error message if no script_ files are present. – user1934428 Jul 06 '18 at 09:04

Multiple bash scripts to execute at a time in a single command

1 Answers1