Extracting the file name from a full path string

Question

Let's say I have a string which represents the full path of a file: full_path='./aa/bb/cc/tt.txt'.

How can I extract only the file name tt.txt?

Please don't tell me to use echo $full_path | cut -d'/' -f 5.

Because the file may be located in a deeper or shallower folder.

The number, 5, cannot be applied in all cases.

Hope this will help: https://stackoverflow.com/a/32372307/2987755 — dkb, Jun 07 '18 at 06:18

score 0 · Answer 1 · answered Jun 07 '18 at 06:18

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if you are comfortable with python then, you can use the following piece of code.

full_path = "path to your file name"
filename = full_path.split('/')[-1]
print(filename)

answered Jun 07 '18 at 06:18

Shubham Jaiswal

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score 0 · Answer 2 · answered Jun 07 '18 at 06:22

Use the parameter expansion functionality.

 full_path='./aa/bb/cc/tt.txt'
 echo ${full_path%/*}

That will give you the output

 ./aa/bb/cc

And will work any number of directory levels deep, as it will give you everything up to the final "/".

Edit: Parameter expansion is very useful, so here's a quick link for you that gives a good overview of what is possible: http://wiki.bash-hackers.org/syntax/pe

score 0 · Answer 3 · answered Jun 07 '18 at 06:27

0

You can use this construct

echo "$full_path" | sed 's/\/.*\///'

answered Jun 07 '18 at 06:27

webmite

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Extracting the file name from a full path string

3 Answers3