Array of Pointer. Get value of a Element of the Pointer

Question

I got an array of pointers of my Class:

myclass *v[3];
myclass *p;
v[0] = p;

I know that I can get the adress with val=v[0]. But how can I get the Value of v[0]?

Well, `*(v[0])`. I think you need a good book on C++, this is not a language you can guess. — YSC, Jun 05 '18 at 13:20
@YSC Parens not always necessary, in this case `*v[0]` will do as well. — CiaPan, Jun 05 '18 at 13:22
`v[0]` is the value, i guess you want the object that pointer is pointing to, but I have to disappoint you: `v[0]` points at garbage — 463035818_is_not_a_number, Jun 05 '18 at 13:22
@CiaPan They are when you're a beginner, which OP is clearly ;) — YSC, Jun 05 '18 at 13:24

score 0 · Accepted Answer · answered Jun 05 '18 at 13:22

0

Use the dereference operator * e.g. *arr[0]

answered Jun 05 '18 at 13:22

Liam Potter

kkica · Answer 2 · 2018-06-05T13:24:04.923

0

v[0] is a pointer. TO access the value of a pointee, you need to dereference it. Use the dereference operator, that is *.

*v[0]

edited Jun 05 '18 at 13:24

answered Jun 05 '18 at 13:23

kkica

2 Answers2