my problem is i'm trying to get pairs by this code:
for (i in 1:4)
{
for (j in 1:4)
{
print(pair(i,j))
}
}
my expected result to be (1,1),(1,2).... not (1L,1L),(1L,2L)
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ahmad alanaqreh
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`pair(i,j) ` (whatever it is) has more then one element. So only first will bi used. – Mislav May 30 '18 at 10:24
1 Answers
0
-- answer to question before edit --
I'm assuming you mean pairlist and not pair.
If so you can do the following:
v <- list(pairlist(1,2),pairlist(3,4))
if (any(sapply(v,identical,pairlist(1,2))))
print(1)
# [1] 1
if (any(sapply(v,identical,pairlist(2,2))))
print(1)
# *nothing happens*
moodymudskipper
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thank you so much , it's working , i have another question please ,now instead of using pair(1,2) i wanna use variables for example:pair(i,j) ,the problem that the R display it like (1L, 2L),do you have any idea how i can keep it with the value of the variable which is integer ??? – ahmad alanaqreh May 30 '18 at 11:11
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I don't understand the issue, you want to be flexible regarding `integer` to `double` comparison ? – moodymudskipper May 30 '18 at 11:16
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Also I'm confused that you keep on saying `pair` and not `pairlist`, what function are you actually using ? – moodymudskipper May 30 '18 at 11:17
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i am using vector called v the mode is "list" ,inside each element i have pairs "v – ahmad alanaqreh May 30 '18 at 11:32
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`L` just means it's an integer, you can write `if (any(sapply(v,identical,pairlist(1L,2L))))` – moodymudskipper May 30 '18 at 11:36
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https://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example – moodymudskipper May 30 '18 at 11:37
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for (i in 1:10) { for (j in 1:11) { if(any(sapply(v[[i]],identical,pair(i,j)))){Y[i,j]=1} } } – ahmad alanaqreh May 30 '18 at 11:59
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not like this :). Poste a `dput` of a sample of your input data, and type exactly what output you would like to get, and edit your question, not the comments, the post I linked should detail all this. – moodymudskipper May 30 '18 at 12:01