Getting class name without instanting an object

Question

class A:
    pass

> A().__class__.__name__ 
-->'A'
> A.__class__.__name__
--> 'type'

How can I get 'A' without the parens?

please you should consider to google before posting such question, — Roushan, Apr 22 '18 at 18:50
@Roushan, that's the case for 96% of the questions ons SO..... — Bart, Apr 22 '18 at 19:28

Błażej Michalik · Accepted Answer · 2018-04-22T19:36:39.273

2

You're getting 'type', because the class of a class definition is... type (in other words: a class definition is a type).

You can just use the __name__ attribute. No need to look for the __class__, you already have the class:

A.__name__

'A'

Just to make it completely clear:

A().__class__ is A

True

edited Apr 22 '18 at 19:36

answered Apr 22 '18 at 19:25

Błażej Michalik

1 Answers1