how to by pass Python key error even when key is present?

Question

error

python code

I am getting an key error even when there's a key present.

print (dict_month[0:4])

[{'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}]

'January' in dict_month

False

'january' in dict_month

False

You have a list of dictionaries, not a dictionary ... January is not a key of dict_month, it's a key for all of your dictionaries. — A.Joly, Mar 09 '18 at 06:55

score 0 · Answer 1 · answered Mar 09 '18 at 06:57

Simple one liner :

>>> any(['January' in ele for ele in l])

#driver values :

IN : l = [{'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}, {'January': 'Sun'}]

OUT : True

The problem with your approach was as A.Joly mentioned, that you have a list of dictionary. Your approach would have been correct for a dictionary.

how to by pass Python key error even when key is present?

1 Answers1