for loop in python with decimal number as step

Question

I want to make a for loop that looks like this:

for x in range(0, 1, 0.1):
    print(x)

obviously it throws this error:

Traceback (most recent call last): File "", line 1, in for i in range(0, 1, 0.1): TypeError: 'float' object cannot be interpreted as an integer

So it there a way in python 3.6 to make a for loop with floating point?

score 11 · Accepted Answer · answered Mar 02 '18 at 01:01

11

use numpy's arange instead of range:

import numpy as np
for x in np.arange(0, 1, 0.1):
    print(x)

answered Mar 02 '18 at 01:01

sacuL

1

Keep in mind you may not get exactly the numbers you expect, because `0.1` can't be represented exactly as a finite binary fraction. I like Simon's approach of using integers and dividing by 10 better; it's less prone to accumulated rounding errors. – kindall Mar 02 '18 at 01:26

score 5 · Answer 2 · answered Mar 02 '18 at 01:02

5

Why not divide an integer and convert it into a float value?

for x in range(0, 10, 1):
    print(x/10)

Here you range from 0 to 10 and the divide the output by 10 to get a floating point.

answered Mar 02 '18 at 01:02

Xantium

yes. I kinda should have thought about this, I guess its past experience from python2.x that made me scared to divide integer – Tissuebox Jul 30 '21 at 07:28

2 Answers2