Python - Write list to text file with \n from re.findall

Question

In reference to a previous question Python Regex - Capture match and previous two lines

I am try to write this match to a text file but it seems to write all the matches on 1 line.

Tried these combinations with no luck

    output = re.findall(r'(?:.*\r?\n){2}.*?random data.*', f.read())

myfilename.write(str(list(output) + '\n')) # gives me TypeError: can only concatenate list (not "str") to list
myfilename.write(str(output)) # writes to one line

Would I need a for loop to iterate each index to a new line, or am I missing something, it should be matching the CRLLF and keep the original format correct?

`myfilename.write("\n".join(output))` or `myfilename.write("\r\n".join(output))` — Wiktor Stribiżew, Feb 22 '18 at 18:52

Jan · Accepted Answer · 2018-02-22T18:59:16.470

1

You could use

with open ("file_here.txt", "r") as fin, open("output.txt", "w") as fout:
    output = re.findall(r'(?:.*\r?\n){2}.*?random data.*', fin.read())
    fout.write("\n".join(output))

edited Feb 22 '18 at 18:59

answered Feb 22 '18 at 18:53

Jan

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Python - Write list to text file with \n from re.findall

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