Bash Conditional Loop Issue Y or y ==> YES N or n==>NO

Question

So the problem is i am not getting the desired output. Need some help in the problem statement as i am a newbie to the BashScript!!

Welcome to stackoverflow, you have to show us by posting samples into your post like what is working and what is not. If you say something is not working without showing us, we can't help on it, please do the needful in your post. — RavinderSingh13, Feb 03 '18 at 07:10
You should be using `=`. `-eq` is for comparing numbers, not strings. — Barmar, Feb 03 '18 at 07:43
See https://stackoverflow.com/questions/47475445/why-does-eq-show-non-numerical-strings-as-equal-in-bash — Barmar, Feb 03 '18 at 07:45
Since `[[` is for pattern matching, try: `if [[ $input = [Yy] ]]` — cdarke, Feb 03 '18 at 07:50

score 1 · Answer 1 · answered Feb 03 '18 at 09:05

1

-eq is for numeric comparisons and all of the strings YES, Y, N and NO evaluate to zero. Hence they'll all match each other.

You should be using = rather than -eq.

However, you can also use regular expressions in bash with something like:

[[ $input =~ [Yy] ]]

That seems much more readable to me.

answered Feb 03 '18 at 09:05

paxdiablo

Or, since this is bash, `[[ ${input^} = Y ]]` – glenn jackman Feb 03 '18 at 12:32

1 Answers1