Remove the first items in a list of lists - make a copy instead of modifying in-place

Question

Let the array a be:

a = [[1, 2], [1, 2, 3], [1, 2, 3, 4]]

How can one obtain the following list?

b = [[2], [2, 3], [2, 3, 4]]

By creating a new list where each entry consists of one entry of the original list without the first element. — mkrieger1, Jan 31 '18 at 16:52
Related: [How do I delete the Nth list item from a list of lists (column delete)?](https://stackoverflow.com/q/13244466/7851470) — Georgy, Jan 08 '20 at 14:06

score 4 · Accepted Answer · edited Jan 08 '20 at 14:05

4

Well, for this example, you could use list comprehension with slicing.

a = [[1, 2], [1, 2, 3], [1, 2, 3, 4]]
b = [x[1:] for x in a]

edited Jan 08 '20 at 14:05

Georgy

answered Jan 31 '18 at 16:52

SuperStew

1 Answers1