Python string formatting to get end of a string

Question

So I know that I can use either the "%" or ".format" syntax to format string, particularly to trim the end of string to a set number of characters:

>>> print("%s" % "12345678990")    
12345678990
>>> print("%.5s" % "12345678990")
12345

Is there any way to trim the beginning of the string using string formatting (not slicing, etc)? The desired output would be:

>>> print("%<lst3>" % "12345678990")    
990

I have tried the following, to no avail:

"%.-3s"

"%.=3s"

"%.:3s"

"%.:-3s"

And so on.

I have seen nothing in the docs about this, but would be happy to be proven wrong! Any help is appreciated.

Answer 1

well for this problem you have to use slicing.

print ("12345678990"[8:])
#or
print ("12345678990"[-3:])

Understanding Python's slice notation will be useful to you.

Answer 2

For strings, taking a slice is more Pythonic:

>>> "12345678990"[-3:]
'990'

Bear in mind the "wrap-around" behavior of negative numbers in slicing and indexing.

Answer 3

You can do like this :

 print("%s" % "12345678990"[-3:])