Trying to assert that two dictionaries that have nested contents are equal to each other (order doesn't matter) with pytest. What's the pythonic way to do this?
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12Have you tried `assert d1 == d2`? Btw what is your nested content? – Szabolcs Nov 09 '17 at 12:07
6 Answers
38
Don't spend your time writing this logic yourself. Just use the functions provided by the default testing library unittest
from unittest import TestCase
TestCase().assertDictEqual(expected_dict, actual_dict)
Vincent Claes
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pytest's magic is clever enough. By writing
assert {'a': {'b': 2, 'c': {'d': 4} } } == {'a': {'b': 2, 'c': {'d': 4} } }
you will have a nested test on equality.
Hawkeye Parker
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linqu
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I guess a simple assert equality test should be okay:
>>> d1 = {n: chr(n+65) for n in range(10)}
>>> d2 = {n: chr(n+65) for n in range(10)}
>>> d1 == d2
True
>>> l1 = [1, 2, 3]
>>> l2 = [1, 2, 3]
>>> d2[10] = l2
>>> d1[10] = l1
>>> d1 == d2
True
>>> class Example:
stub_prop = None
>>> e1 = Example()
>>> e2 = Example()
>>> e2.stub_prop = 10
>>> e1.stub_prop = 'a'
>>> d1[11] = e1
>>> d2[11] = e2
>>> d1 == d2
False
Szabolcs
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6
General purpose way is to:
import json
# Make sure you sort any lists in the dictionary before dumping to a string
dictA_str = json.dumps(dictA, sort_keys=True)
dictB_str = json.dumps(dictB, sort_keys=True)
assert dictA_str == dictB_str
William
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3works, but it's very tedious to find the difference between the two objects afterwards – linqu Jan 29 '21 at 20:53
0
assert all(v == actual_dict[k] for k,v expected_dict.items()) and len(expected_dict) == len(actual_dict)
Damel Lambert-Powell
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3This is unnecessary. If two dicts are equal then necessarily their lengths will be the same, and so will be their elements. Barely `dict1==dict2` does the trick. Also to be rigurous, if item per item check was neccesary, you would need to go over the nested elements too. – Aug 23 '18 at 21:26
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Said simple evaluation does exactly a multi-dimension-wise check, as opposed to the `is` operator, that solely checks for the memory pointer. – Aug 23 '18 at 21:29
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your question is not very specific but with what i can understand, you are either trying to check if the length are the same
a = [1,5,3,6,3,2,4]
b = [5,3,2,1,3,5,3]
if (len(a) == len(b)):
print True
else:
print false
or checking if the list values are the same
import collections
compare = lambda x, y: collections.Counter(x) == collections.Counter(y)
compare([1,2,3], [1,2,3,3])
print compare #answer would be false
compare([1,2,3], [1,2,3])
print compare #answer would be true
but for dictionaries you could also use
x = dict(a=1, b=2)
y = dict(a=2, b=2)
if(x == y):
print True
else:
print False
Adeojo Emmanuel IMM
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