Call multiple dictionaries who names involve i in a loop?

Question

I would like to call multiple dictionaries using a for loop. I am unsure how to call multiple dictionaries properly, and I can't figure out if its possible using concatenation. The code below should explain my thinking even though the print statement is incorrect.

stat0 = {}
stat0["bob"] = 0
stat1 = {}
stat1["bob"] = 0
stat2 = {}
stat2["bob"] = 0

for i in range(3):
    print(stat(i))

Possible duplicate of [How to get the value of a variable given its name in a string?](https://stackoverflow.com/questions/9437726/how-to-get-the-value-of-a-variable-given-its-name-in-a-string) — Elis Byberi, Oct 27 '17 at 15:45

score 2 · Answer 1 · answered Oct 26 '17 at 20:48

2

How about putting them in a collection, and then getting value generically:

for hm in [stat0, stat1, stat2]
    print(hm["bob"])

answered Oct 26 '17 at 20:48

pellucidcoder

131
4
9

score 1 · Answer 2 · answered Oct 26 '17 at 20:47

Instead of naming your dictionaries, just put them into another dictionary:

#UNTESTED
stat = { 0: stat0, 1: stat1, 2: stat2 }
for i in range(3):
    print(stat[i])

Or, use an iterative style more appropriate for dict:

#UNTESTED
for i, d in stat.items():
    print(i, d)

Call multiple dictionaries who names involve i in a loop?

2 Answers2