Checking whether a password contains only two capital letters using REGEX

Asked Oct 20 '17 at 08:53

Active Oct 20 '17 at 08:55

Viewed 27 times

I want to construct a regex to check whether only two CAPITAL letters are present in a password.

CODE1

import re
re.search(r'\A(?=.*[A-Z])','PassWords')
<_sre.SRE_Match object; span=(0, 0), match=''>

CODE2

re.search(r'\A(?=.*[A-Z])','PassWorDs')
<_sre.SRE_Match object; span=(0, 0), match=''>

Code2 contains 3 capital letters, but re matched that too. I don't want that. Where should I apply the quantifier

edited Oct 20 '17 at 08:55

DeepSpace

asked Oct 20 '17 at 08:53

Fuji Komalan

Why did you tag this `nsregularexpression`? Just adding random tags? – melpomene Oct 20 '17 at 08:55
@melpomene it was a mistake. – Fuji Komalan Oct 20 '17 at 08:57
1

`re.search(r'\A(?=(?:[^A-Z]*[A-Z]){2}[^A-Z]*\Z)','PassWorDs')` – Wiktor Stribiżew Oct 20 '17 at 08:58
Why do everything in a look-ahead? – melpomene Oct 20 '17 at 08:58
Like [THIS](https://regex101.com/r/qzdzou/1)? – Gurmanjot Singh Oct 20 '17 at 08:59
@Gurman No, that regex matches at least 2 uppercase letters. See my suggestion above. That is what OP is looking for. – Wiktor Stribiżew Oct 20 '17 at 09:01
@WiktorStribiżew You are correct, again. Thanks for pointing that out. :) [updated](https://regex101.com/r/qzdzou/2) – Gurmanjot Singh Oct 20 '17 at 09:04

0 Answers0