Converting String element to int inside a tuple in Python

Question

I have a tuple a = (('1414', 'A'), ('1416', 'B')) and I need to obtain the result as result = ((1414, 'A'), (1416, 'B')).

I tried tuple([map(int, x[0]) for x in a]) based on How to convert strings into integers in Python? and I get the result as ([1414], [1416]). How would I maintain the result as a tuple with the changed value instead of making it as a list?

Answer 1

Using a generator expression:

a = (('1414', 'A'), ('1416', 'B'))

result = tuple((int(x[0]), x[1]) for x in a)

Answer 2

Using map:

azip = list(zip(*a))
out = list(zip(map(int, azip[0]), azip[1]))

Answer 3

You can use a lambda in map() which converts the first element in the tuple to an int.

a = (('1414', 'A'), ('1416', 'B'))
result = tuple(map(lambda x: (int(x[0]), x[1]), a))

Answer 4

You can do :

print(tuple([(int(i[0]),i[1]) for i in a]))

for detailed solution :

a = (('1414', 'A'), ('1416', 'B'))

new_list=[]

for i in a:
    new_list.append((int(i[0]),i[1]))

print(tuple(new_list))