I have this line at the end of my bash file:
ab -n 100 -c 10 'https://example.com/?bot_id=$BOT_ID&page_id=$PAGE_ID'
Since I have 2 parameters in my query string, I need to surround the URL with quotes.
The problem is the bash is outputting the variable name ($BOT_ID) instead of the value of it.
How could I output the value inside the quotes?
Use double quotes so the shell expands the variables; using single quotes keep the value as-is
[root@box ~]# a=5
[root@box ~]# echo '$a'
$a
[root@box ~]# echo "$a"
5
Rule of thumb: always double quote your variables in bash.
from TLDP docs: When referencing a variable, it is generally advisable to enclose its name in double quotes. This prevents reinterpretation of all special characters within the quoted string -- except $, ` (backquote), and \ (escape).
you should use "" :
ab -n 100 -c 10 "https://example.com/?bot_id=$BOT_ID&page_id=$PAGE_ID"
