how to compare string with a dynamic text in java?

Question

There is a string: "Login 1234 has been created" Here 1234 is a dynamic text. How can I compare this entire string in one shot.

I do know of the way to do split using " "(space) and then getting into array,asserting it using regex:

assertTrue(dynamicText.substring(1, 5).equals([0-9]+));

but that takes more lines of code. I want to know if there is any efficient way of coding other than this. Thanks.

It is wierd to use an output text as input for your program to work. Don't you have the variable that contains 1234 somewhere ? — Seaskyways, Sep 26 '17 at 05:59
Do you just want to check of the string has a sequence of numbers in it? — Sweeper, Sep 26 '17 at 06:06
@Sweeper I want to check the entire String along with the dynamic text. — codefemme, Sep 26 '17 at 06:07
If the entire string matches what is the logic of checking the dynamic part also. If you have the variable part already just create the expected string in your code and compare with the actual one. — Grasshopper, Sep 26 '17 at 06:12

score 1 · Answer 1 · answered Sep 26 '17 at 06:14

1

I found the solution:

String expected = "Login 1234 has been created";
        if(expected.matches("Login ([0-9]+) has been created"))
        {
            System.out.println("matched");
        }

answered Sep 26 '17 at 06:14

codefemme

63
2
11

score 0 · Answer 2 · answered Sep 26 '17 at 06:06

There are primarily two assertions visible with your input:

Asserting statics in the output

assertTrue(dynamicText.contains("Login") && dynamicText.contains("has been created"));

String userInput = "1234"; 
// if there is a dynamic variable provided as an input this has to be there in your code somewhere

assertTrue(dynamicText.substring(1, 5).equals(userInput));

The reason that the input has to be there is otherwise you would end up reading static text from WebElements found by you.

Hence in short

String expectedOutput = "Login " + userInput + " has been created.";
assertTrue("The expected output is different!", dynamicText.equals(expectedOutput));

How does this works when comparing the template `{"name" : "$name", "age" : "$age"}` with `{"name" : "Bob", "age" : 47}` at https://stackoverflow.com/questions/51146644/compare-dynamic-xml-json-content-with-static-payload — Kanagavelu Sugumar, Jul 03 '18 at 04:52

score 0 · Answer 3 · answered Sep 26 '17 at 06:06

Use regular expression:

if (s.matches("Login \\S+ has been created")) {
    // code here
}

If you need the login name, you can't use that convenience method, but have to use the Pattern class directly:

Pattern p = Pattern.compile("Login (\\S+) has been created");
Matcher m = p.matcher(s);
if (m.matches()) {
    String login = m.group(1);
    // code here
}

how to compare string with a dynamic text in java?

3 Answers3