25

I have an array of URLs to scrape data from:

urls = ['url','url','url'...]

This is what I'm doing:

urls.map(async (url)=>{
  await page.goto(url);
  await page.waitForNavigation({ waitUntil: 'networkidle' });
})

This seems to not wait for page load and visits all the URLs quite rapidly (I even tried using page.waitFor).

I wanted to know if am I doing something fundamentally wrong or this type of functionality is not advised/supported.

ggorlen
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ahhmarr
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5 Answers5

34

map, forEach, reduce, etc, does not wait for the asynchronous operation within them, before they proceed to the next element of the iterator they are iterating over.

There are multiple ways of going through each item of an iterator synchronously while performing an asynchronous operation, but the easiest in this case I think would be to simply use a normal for operator, which does wait for the operation to finish.

const urls = [...]

for (let i = 0; i < urls.length; i++) {
    const url = urls[i];
    await page.goto(`${url}`);
    await page.waitForNavigation({ waitUntil: 'networkidle2' });
}

This would visit one url after another, as you are expecting. If you are curious about iterating serially using await/async, you can have a peek at this answer: https://stackoverflow.com/a/24586168/791691

Julien Le Coupanec
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tomahaug
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  • Wierd, this gives `await page.goto(`${url}`);` Unexpected identifier syntaxErrpr. – user2875289 Nov 01 '17 at 10:42
  • @user2875289 Which version of node are you using? You need to use 7.6 or higher to have async/await work without doing transpiling. – tomahaug Nov 01 '17 at 11:22
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    @tomahaug I'm using Node 8.9. The problem was solved. I was using async/wait mixed with promises that cause the syntaxError. It works now after changing to async/wait only. Thanks! – user2875289 Nov 01 '17 at 11:28
  • Hi @MehranShafqat, it might be better to post this as a new question rather than a comment – tomahaug Apr 23 '20 at 13:37
7

The accepted answer shows how to serially visit each page one at a time. However, you may want to visit multiple pages simultaneously when the task is embarrassingly parallel, that is, scraping a particular page isn't dependent on data extracted from other pages.

A tool that can help achieve this is Promise.allSettled which lets us fire off a bunch of promises at once, determine which were successful and harvest results.

For a basic example, let's say we want to scrape usernames for Stack Overflow users given a series of ids.

Serial code:

const puppeteer = require("puppeteer");

(async () => {
  const browser = await puppeteer.launch({dumpio: false});
  const [page] = await browser.pages();
  const baseURL = "https://stackoverflow.com/users";
  const startId = 6243352;
  const qty = 5;
  const usernames = [];
  
  for (let i = startId; i < startId + qty; i++) {
    try {
      await page.goto(`${baseURL}/${i}`);
      usernames.push(await page.$eval(
        ".profile-user--name", 
        el => el.children[0].innerText
      ));
    }
    catch (err) {}
  }

  console.log(usernames.length);
  await browser.close();
})();

Parallel code:

const puppeteer = require("puppeteer");

(async () => {
  const browser = await puppeteer.launch({dumpio: false});
  const baseURL = "https://stackoverflow.com/users";
  const startId = 6243352;
  const qty = 5;

  const usernames = (await Promise.allSettled(
    [...Array(qty)].map(async (_, i) => {
      const page = await browser.newPage();
      await page.goto(`${baseURL}/${i + startId}`);
      return page.$eval(
        ".profile-user--name", 
        el => el.children[0].innerText
      );
    })))
    .filter(e => e.status === "fulfilled")
    .map(e => e.value)
  ;
  console.log(usernames.length);
  await browser.close();
})();

Remember that this is a technique, not a silver bullet that guarantees a speed increase on all workloads. It will take some experimentation to find the optimal balance between the cost of creating more pages versus the parallelization of network requests on a given particular task and system.

The example here is contrived since it's not interacting with the page dynamically, so there's not as much room for gain as in a typical Puppeteer use case that involves network requests and blocking waits per page.

Of course, beware of rate limiting and any other restrictions imposed by sites (running the code above may anger Stack Overflow's rate limiter).

For tasks where creating a page per task is prohibitively expensive or you'd like to set a cap on parallel request dispatches, consider using a task queue or combining serial and parallel code shown above to send requests in chunks. This answer shows a generic pattern for this agnostic of Puppeteer.

These patterns can be extended to handle the case when certain pages depend on data from other pages, forming a dependency graph.

See also Using async/await with a forEach loop which explains why the original attempt in this thread using map fails to wait for each promise.

ggorlen
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2

If you find that you are waiting on your promise indefinitely, the proposed solution is to use the following:

const urls = [...]

for (let i = 0; i < urls.length; i++) {
    const url = urls[i];
    const promise = page.waitForNavigation({ waitUntil: 'networkidle' });
    await page.goto(`${url}`);
    await promise;
}

As referenced from this github issue

Neil
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0

Something no one else mentions is that if you are fetching multiple pages using the same page object it is crucial that you set its timeout to 0. Otherwise, once it has fetched the default 30 seconds worth of pages, it will timeout.

  const browser = await puppeteer.launch();
  const page = await browser.newPage();
  page.setDefaultNavigationTimeout(0);
user3483642
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-1

Best way I found to achieve this.

 const puppeteer = require('puppeteer');
(async () => {
    const urls = ['https://www.google.com/', 'https://www.google.com/']
    for (let i = 0; i < urls.length; i++) {

        const url = urls[i];
        const browser = await puppeteer.launch({ headless: false });
        const page = await browser.newPage();
        await page.goto(`${url}`, { waitUntil: 'networkidle2' });
        await browser.close();

    }
})();
Mehran Shafqat
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  • I don't see a point in all these `browser.newPage()` and `browser.close()` calls. Since you're working serially, you can make one `page` before the loop and navigate it from one page to the next using `goto`s, then close the browser after the loop ends. – ggorlen Nov 25 '20 at 07:40