when the if statement checks 'coffee' or 'c' I want is to also be able to check all forms of those too. I.e CofFeE should work but not cofe

Question

coffeortea = input("Would you like coffee or tea? ")
if 'coffee' == coffeortea:
    print("1")
elif 'c' == coffeortea:
    print("2")
else:
    print("3")

I would like it if the user types coFfeE to print 1. or if the user types C to type 2. Basically, I want upper and lower case to not be an issue.

Possible duplicate of [How to convert string to lowercase in Python?](https://stackoverflow.com/questions/6797984/how-to-convert-string-to-lowercase-in-python) — hnefatl, Sep 18 '17 at 18:31

score 2 · Answer 1 · edited Sep 18 '17 at 18:38

2

Compare on the if clauses everything uppercase or lowercase

coffeortea = input("Would you like coffee or tea? ")
if 'coffee' == coffeortea.lower():
    print("1")
elif 'c' == coffeortea.lower():
    print("2")
else:
    print("3")

edited Sep 18 '17 at 18:38

Abe

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answered Sep 18 '17 at 18:31

francisco sollima

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score 0 · Answer 2 · answered Sep 18 '17 at 18:37

You can receive your input with properly convertion to str, with lower() function call, and then, make your condition basing on that:

coffeortea = str(raw_input("Would you like coffee or tea? ")).lower()
if 'coffee' == coffeortea:
    print("1")
elif 'c' == coffeortea:
    print("2")
else:
    print("3")

when the if statement checks 'coffee' or 'c' I want is to also be able to check all forms of those too. I.e CofFeE should work but not cofe

2 Answers2