"List index out of range" error when iterated with for loop

Question

I am beginner. I am writing a python program that removes '!' and '.' from the list. User enters any string. Python converts it into a list and removes ! and . and again prints the altered list. Here is my code :

x = input("Enter a string: ")

y = list(x)

for i in range(len(y) - 1):

    if y[i] == '!' or y[i] == '.':
        y.pop(i)
print("Altered list is: ",y)

Even when I do range(len(y)-1) to range(len(y)) it shows the error:
List index out of range.

You're modifying the list on each iteration by deleting items from it. Don't do that. Instead, rebuild your list that contains the items you want to keep. — roganjosh, Sep 16 '17 at 16:24
Thank you everyone for the help. I wasn't just getting that simple point thanks again. — user8619561, Sep 16 '17 at 16:34
@Jean-FrançoisFabre I am curious to know other way. please tell. — user8619561, Sep 16 '17 at 16:35
follow the "original" question, you'll see a lot of different ways. This is a classic duplicate on that site. — Jean-François Fabre, Sep 16 '17 at 16:37

score 0 · Accepted Answer · answered Sep 16 '17 at 16:24

0

You are iterating over the list that you are modifying... It cannot end well.

Try this approach instead:

y = [elt for elt in y if elt != "!" or elt != "."]

It will rebuild your list, omitting the undesired elements.

answered Sep 16 '17 at 16:24

Reblochon Masque

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Thanks Reblochon. – user8619561 Sep 16 '17 at 16:34

"List index out of range" error when iterated with for loop

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