How to apply a function to an object in the chrome console

Question

Below is the code I unsuccessfully try to run in the console of chrome. Now the code of which looks like this and does not actually work.

Test.provide = Test.data = function arraaays() {
const c = [];

for (let i = 0; i < Math.max(a.length, b.length); i++) {
    if (a[i] !== undefined) {
        c.push(a[i]);
    }

    if (b[i] !== undefined) {
        c.push(b[i]);
    }
}

console.log(c);
}

The code itself should interact with two arrays that are in Test.data and create a new one of this type on their basis

a: ['a', 'b', 'c'] //first array
b: ['d', 'e'] //second array
c: ['a', 'd', 'b', 'e', 'c'] // new array

how are you running that function? and what is `Test` anyway? — Jaromanda X, Sep 15 '17 at 03:35
`The code itself should interact with two arrays that are in Test.data` - you've clobbered `Test.data` with the function — Jaromanda X, Sep 15 '17 at 03:36
[Possible related question](https://stackoverflow.com/questions/3975170/javascript-how-to-join-combine-two-arrays-to-concatenate-into-one-array) — Ram, Sep 15 '17 at 03:37
and, also, the result will actually be `[ "a", "d", "b", "e", "c", undefined ]` - because `undefined !== null` — Jaromanda X, Sep 15 '17 at 03:38

score 0 · Accepted Answer · answered Jan 29 '18 at 17:10

function arry(a, b) {
var c = [];

for (let i = 0; i < Math.max(a.length, b.length); i++) {
    if (a[i] != undefined) {
        c.push(a[i]);
    }

    if (b[i] != undefined) {
        c.push(b[i]);
    }
}
return c;
}
Test.provide = arry(Test.data.a, Test.data.b);

How to apply a function to an object in the chrome console

1 Answers1