how to use regex to add leading zero

Question

Question - what is the shortest form of regex to add a leading zero into a found pattern?

I want to add a leading zero to any number that matches this regex pattern

[(][0-9][0-9][0-9][0-9][-][0-9][0-9][0-9][0-9][-][0-9][0-9][)]

I am using Notepad++.

Please post a sample text and expected output. What have you tried? — Wiktor Stribiżew, Aug 14 '17 at 17:48
You mean you want to add a leading zero in front of a number that matches `$\d{4}-\d{4}-\d{2}$`? — Ken White, Aug 14 '17 at 17:57
Can't you just `concatenate` a `0` on to it if it does match that pattern? Example: `newString = "0" + matchedPatter;` — demogorgon, Aug 14 '17 at 18:00

score 0 · Answer 1 · answered Aug 14 '17 at 22:23

0

In Notepad++ Regex Replace, you use $n to represent the nth capture group for replacement:

Search for: [(]([0-9][0-9][0-9][0-9][-][0-9][0-9][0-9][0-9][-][0-9][0-9])[)]
Replace with: (0$1)

answered Aug 14 '17 at 22:23

NetMage

1 Answers1