What is difference between Array.isArray and jQuery.isArray?

Question

They seem to be the same.

Internally jQuery just maps its own $.isArray to the native Array.isArray.*

https://stackoverflow.com/questions/22289727/difference-between-using-array-isarray-and-instanceof-array — Anant Kumar Singh, Jul 19 '17 at 06:37
Maybe it's a compatibility thing. Try checking previous revisions of this function — Alon Eitan, Jul 19 '17 at 06:39
https://github.com/jquery/jquery/commit/1b9575b9d14399e9426b9eacdd92b3717846c3f2 — Alon Eitan, Jul 19 '17 at 06:46
@AlivetoDie Your link points to unrelated question. It seems to be similar, but it isn't. How it can help me? — Victor Dombrovsky, Jul 19 '17 at 11:38
@AlonEitan Probably. But why it isn't deprecated, if it just maps to a native function? — Victor Dombrovsky, Jul 19 '17 at 11:40
@VictorDombrovsky I don't actually know why. I can only guess that it's there for backwards compatibility reasons — Alon Eitan, Jul 19 '17 at 11:41
@sotirios-delimanolis How this question may be opinion based? If there is any difference, then it may be clearly defined. No opinion is involved. — Victor Dombrovsky, Jul 19 '17 at 11:44
@VictorDombrovsky Please [read this](http://blog.jquery.com/2017/03/16/jquery-3-2-0-is-out/) (_Deprecated `jQuery.isArray`_) — Alon Eitan, Jul 19 '17 at 12:05

score 9 · Accepted Answer · answered Jul 19 '17 at 12:29

After further investigation I found this commit where they replaced jQuery.isArray with the native Array.isArray().

They also announced here that $.isArray is officially deprecated.

The function still exist for backward compatibility but I guess it will be dropped completly in a future jQuery release.

score 3 · Answer 2 · edited Jul 19 '17 at 07:06

3

There is no difference.

jQuery just prototype the JavaScript's native isArray function.

something that will look like-

jQuery.prototype.isArray = Array.isArray;

edited Jul 19 '17 at 07:06

Anant Kumar Singh

answered Jul 19 '17 at 06:34

Sagar V

OP is in confusion and it is OP's assumption that both are same. This answer confirming it. @AlivetoDie – Sagar V Jul 19 '17 at 06:36
For what reason? If it would be for backward compatibility, it should be marked as deprecated, but it isn't. – Victor Dombrovsky Jul 19 '17 at 11:54

2 Answers2