How to print an exception?

Question

How to print python exception?

Example:

try:
    action()
except:
    print "Unexpected error:", sys.exc_info()[0]

Prints:

Unexpected error: <type 'exceptions.TypeError'>

It does not have much information for me.

note the simple way too : `except Exception as e`, with `print e` — PRMoureu, Jul 16 '17 at 17:44
Well what about them? Did you do any research? https://stackoverflow.com/questions/22232201/how-in-python-find-where-exception-was-raised, https://stackoverflow.com/questions/4690600/python-exception-message-capturing, ... — jonrsharpe, Jul 16 '17 at 17:45
Possible duplicate of [How to print an exception in Python?](https://stackoverflow.com/questions/1483429/how-to-print-an-exception-in-python) — Boris Verkhovskiy, Sep 23 '19 at 04:52

score 5 · Accepted Answer · answered Jul 16 '17 at 17:41

5

try:
    action()
except:
    import traceback
    traceback.print_exc()

answered Jul 16 '17 at 17:41

phd

score 0 · Answer 2 · answered Mar 24 '20 at 19:23

0

You can print the exception which occurred too.

try:
    action()
except exception as ex:
    print("Exception: " + str(ex))

answered Mar 24 '20 at 19:23

Sukirti Arya

2 Answers2