python regax search

Question

I have to find the last occurrence of an ip address in a string using regex. I found this

addr = re.search(r'\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}', program[line])

which finds the first occurrence. How can I change it to find the last one?

This is not a duplicate of either of those questions. To the OP: if this wasn't marked duplicate I could give you a detailed explanation. The definitive answer is `.*(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})` where the ip is in capture group 1. So, `if ( (match=re.search(r'.*(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})', program[line]) ) ip = match.group(1)` — , Jul 07 '17 at 18:02

score 1 · Answer 1 · answered Jul 07 '17 at 17:21

1

re.findall(pattern, string)[-1]

answered Jul 07 '17 at 17:21

Alex Hall

I tried this, but I just get an error because the index is out of range... edit: findall just returns a blank list for some reason, and therefore the [-1] is out of range... – Dina Gurevich Jul 07 '17 at 17:25
@DinaGurevich that means there were no matches. – Alex Hall Jul 07 '17 at 17:27

1 Answers1