Determine each character of a string if it contains full width characters in java

Question

I'm searching for a solution on how to manually check each character of a string if it contains any full width characters but I can't find any solution. Can someone help me? This is what I have so far

public boolean areAnyFullWidth(String input) {
    for (char c : input.toCharArray())
        if ((c & 0xff00) == 0xff00)
            return true;
        return false;
}

full width characters are letters or numbers like this ａｓｄ１２３－４５ — healer, Jun 13 '17 at 01:36
I just follow the instruction in this link sir [link](https://stackoverflow.com/questions/29508932/how-check-if-string-has-full-width-character-in-java) — healer, Jun 13 '17 at 01:37
@ErwinBolwidt When i say letters or numbers like this I mean characters that taking a much wider space in computer compare to a normal one — healer, Jun 13 '17 at 01:39
I just found that link: https://stackoverflow.com/questions/29508932/how-check-if-string-has-full-width-character-in-java - so, it completely describes how to check for "full width" characters. What specific question do you have that is *not* answered by that post? — Erwin Bolwidt, Jun 13 '17 at 01:41
I want to restrict an input string with full width characters regarding of what character is it. His code accept full width characters like chinese and japanese letters — healer, Jun 13 '17 at 01:44
@healer Ok, if that's what your issue is, **edit** (see link under) the question and put it in there. — Erwin Bolwidt, Jun 13 '17 at 02:56

score 1 · Answer 1 · answered Jun 13 '17 at 01:43

If you know the start and end unicode full width range then things are very simple.

Say the range is 0xFFOO to 0xFFEF:

public boolean areAnyFullWidth(String input) {
    for(char c : input.toCharArray())
        if(c >= 0xFFOO && c <= 0xFFEF)
            return true;
        return false;
}

Determine each character of a string if it contains full width characters in java

1 Answers1