Get Filename Without Extension in Python

Question

If I have a filename like one of these:

1.1.1.1.1.jpg

1.1.jpg

1.jpg

How could I get only the filename, without the extension? Would a regex be appropriate?

Does this answer your question? [How to get the filename without the extension from a path in Python?](https://stackoverflow.com/questions/678236/how-to-get-the-filename-without-the-extension-from-a-path-in-python) — Seanny123, Jan 10 '20 at 21:02

score 214 · Accepted Answer · answered Dec 14 '10 at 22:30

214

In most cases, you shouldn't use a regex for that.

os.path.splitext(filename)[0]

This will also handle a filename like .bashrc correctly by keeping the whole name.

answered Dec 14 '10 at 22:30

Marcelo Cantos

4

Does not work properly with "git-1.7.8.tar.gz", where it only removes the ".gz". I use `basename[:-len(".tar.gz")]` for this. – blueyed Dec 09 '11 at 14:10
28

@blueyed: "Does not work properly" is a matter of perspective. The file *is* a gzip file, who's base name is `git-1.7.8.tar`. There is no way to correctly guess how many dots the caller wants to strip off, so `splitext()` only strips the last one. If you want to handle edge-cases like `.tar.gz`, you'll have to do it by hand. Obviously, you can't strip all the dots, since you'll end up with `git-1`. – Marcelo Cantos Dec 09 '11 at 22:29

score 27 · Answer 2 · answered Dec 14 '10 at 22:32

27

>>> import os
>>> os.path.splitext("1.1.1.1.1.jpg")
('1.1.1.1.1', '.jpg')

answered Dec 14 '10 at 22:32

Lennart Regebro

score 11 · Answer 3 · answered Oct 24 '18 at 16:29

11

You can use stem method to get file name.

Here is an example:

from pathlib import Path

p = Path(r"\\some_directory\subdirectory\my_file.txt")
print(p.stem)
# my_file

answered Oct 24 '18 at 16:29

Vlad Bezden

score 10 · Answer 4 · answered Dec 15 '10 at 00:10

10

If I had to do this with a regex, I'd do it like this:

s = re.sub(r'\.jpg$', '', s)

answered Dec 15 '10 at 00:10

Alan Moore

score 6 · Answer 5 · answered Dec 14 '10 at 22:33

6

No need for regex. os.path.splitext is your friend:

os.path.splitext('1.1.1.jpg')
>>> ('1.1.1', '.jpg')

answered Dec 14 '10 at 22:33

Kenan Banks

5 Answers5